Question

How to to get the word at start of string with regular expression in Python

Answer 1

import re     
 
s = 'python xyx 234 aa4!@!4XY.aaAyyy984a ABCa-xYxx3yYa x aa.'   
pattern = r'^\w+'  # word at start of string
 
for match in re.findall(pattern, s):         
    print('Found: {!r}'.format(match))
     
     
'''
run:
 
Found: 'python'
 
'''

 

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Answer 2

import re     
  
s = 'python xyx 234 aa4!@!4XY.aaAyyy984a ABCa-xYxx3yYa x aa.'  
pattern = r'^\w+'  # word at start of string

se = re.search(pattern, s)             

print(se)
print(se[0])

      
      
'''
run:

<_sre.SRE_Match object; span=(0, 6), match='python'>
python

'''

 

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