Question

How to find pattern matches with * in a string with regular expression in Python

Answer 1

import re     

s = 'xyxxxyyyxyxxyy'    
pattern = 'xy*'  # 'x' followed by zero or more 'y' 

for match in re.findall(pattern, s):         
    print('Found: {!r}'.format(match))
    
    
'''
run:

Found: 'xy'
Found: 'x'
Found: 'x'
Found: 'xyyy'
Found: 'xy'
Found: 'x'
Found: 'xyy'

'''

 

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