Question

How to remove the N digit from a number in Java

Answer 1

public class MyClass {
    public static int reverse_number(int num) {
        int reminder = 0, reverse = 0;
        while (num != 0) {    
            reminder = num % 10;      
            reverse = reverse * 10 + reminder;    
            num /= 10;    
        }
        return reverse;
    } 
     
    public static int delete_digit(int num, int n_digit) { 
        int rev_new_num = 0; 
        int l = (int)Math.log10(num) + 1; 
            
        for (int i = 0; num != 0; i++) { 
            int digit = num % 10; 
            num = num / 10; 
         
            if (i != l - n_digit) {
                rev_new_num = (rev_new_num * 10) + digit; 
            }
        }
        return reverse_number(rev_new_num); 
    } 
      
    public static void main(String args[]) {
        int num = 37598; 
     
        System.out.println(delete_digit(num, 3));
        System.out.println(delete_digit(num, 1));
        System.out.println(delete_digit(num, 5));
    }
}
  
  
  
/*
run:
  
3798
7598
3759
  
*/

 

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Answer 2

public class MyClass {
    public static int remove_the_N_digit(int num, int N) {
        String str = Integer.toString(num);
   
        str = str.substring(0, N) + str.substring(N + 1);
         
        return Integer.parseInt(str);
    }
          
    public static void main(String args[]) {
        int num = 870615;
          
        num = remove_the_N_digit(num, 3);
            
        System.out.println(num);
    }
}
    
    
    
    
/*
run:
    
87015
    
*/

 

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