Question

How to recursively count the digits of a number in Python

Answer 1

def count_digits(n):
    if (n != 0):
        count_digits.counter += 1
        count_digits(int(n/10))
    return count_digits.counter;       
count_digits.counter = 0
  

n = 98257

print(count_digits(n))



'''
run:

5

'''

 

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