Question

How to count appearance of all values in int array using C

Answer 1

#include <stdio.h>

void count_appearance_all(int arr[], int arr_size, int count[]) {
    for (int i = 0; i < arr_size; i++) {
        count[arr[i]]++;
    }
}

int main()
{
    int arr[] = {1, 2, 3, 4, 4, 4, 5, 7, 8, 8, 8, 8, 9, 9}; 
    int count[10] = {0};
    int arr_size = sizeof(arr)/sizeof(arr[0]);

    count_appearance_all(arr, arr_size, count);
    
    for (int i = 0; i < 10; i++) {
        if (count[i] != 0) {
            printf("%i %i\n", i, count[i]);
        }
    }

    return 0;
}



/*
run:

1 1
2 1
3 1
4 3
5 1
7 1
8 4
9 2

*/

 

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