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How to determining if an integer is a power of 2 in Python



141 views
asked Mar 26, 2019 by avibootz
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1 Answer

0 votes 
n = 16
      
print(bin(n))
print(bin(n - 1))
print(bin(n & (n - 1)))
 
b = (n & (n - 1)) == 0
  
print(b)
 
 
'''
run:
 
0b10000
0b1111
0b0
True
 
'''

 



answered Mar 26, 2019 by avibootz
edited Mar 26, 2019 by avibootz

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