Question

How to get the minimum (min) of two integers with bitwise operators in C++

Answer 1

#include <iostream>

using namespace std;

int main() {
	int x = 5, y = 9;   
    int min = y ^ ((x ^ y) & -(x < y)); 
    cout << "min = " << min << endl;
     
    x = 7, y = 2;   
    min = y ^ ((x ^ y) & -(x < y)); 
    cout << "min = " << min << endl;
     
    x = -5, y = 3;   
    min = y ^ ((x ^ y) & -(x < y)); 
    cout << "min = " << min << endl;
     
    x = 3, y = -1;   
    min = y ^ ((x ^ y) & -(x < y)); 
    cout << "min = " << min << endl;
}


/*
run:

min = 5
min = 2
min = -5
min = -1

*/

 

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