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How to check if a number has same number of set and unset bits in C++

1 Answer

0 votes
#include <iostream>
  
using namespace std; 
  
void print_bits(unsigned int n) { 
    for (int i = 7; i >= 0; i--)
       cout << ((n >> i) & 1);
    cout << endl;
}
  
bool check_same_set_and_unset_bits(int n) { 
    int set = 0, unset = 0; 
    
    while (n) { 
        if (n & 1) 
            set++; 
        else
            unset++; 
        n = n >> 1; 
    } 
    
    if (set == unset) 
        return true; 
    
    return false; 
} 
    
int main() 
{ 
    int n = 178; 
    
    print_bits(n);
    
    if (check_same_set_and_unset_bits(n)) 
        cout << "Yes" << endl; 
    else
        cout << "No" << endl; 
        
    n = 179; 
    
    print_bits(n);
    
    if (check_same_set_and_unset_bits(n)) 
        cout << "Yes" << endl; 
    else
        cout << "No" << endl; 
      
    return 0; 
} 
 
 
  
/*
run:
  
10110010
Yes
10110011
No

*/

 



answered Mar 11, 2019 by avibootz
edited Mar 11, 2019 by avibootz

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