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How to find non-repeated characters in a string with C

1 Answer

0 votes
#include <stdio.h>
#include <string.h>
 
void getNonRepeatedCharacters(char *s) { 
    int ascii_count[256]; 

    int i; 
    for (i = 0; *(s+i); i++) 
        if(*(s+i)!=' ') 
            ascii_count[(int)*(s+i)]++; 
    
	int n = i; 
   
    char new_s[26] = "";
    for (int j = 0, i = 0; i < n; i++) 
        if (ascii_count[(int)*(s+i)] == 1) 
            new_s[j++] += s[i]; 
	
    strcpy(s, new_s);
} 
   

int main(int argc, char **argv) 
{
	char s[] = "c++ programming"; 
     
    getNonRepeatedCharacters(s); 
     
    puts(s);
     
    return 0; 
}
  
    
/*
run:
  
cpoain
  
*/

 



answered Feb 11, 2019 by avibootz

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