Question

How to parse string to multiple long double numbers in C

Answer 1

#include <stdio.h>
#include <stdlib.h>
 
int main()
{
    char s[] = "3.14 8721.809 52345.81";
    char *end;
    long double n1, n2, n3;
     
    n1 = strtold(s, &end);
    n2 = strtold(end, &end);
    n3 = strtold(end, NULL);
     
    printf("%g %g %g\n", (double)n1, (double)n2, (double)n3);
}
  
/*
 
run:
 
3.14 8721.81 52345.8
 
*/

 

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Answer 2

#include <stdio.h>
#include <stdlib.h>
#include <errno.h>

int main()
{
    char *p = "3.14 8721.809 52345.81";
    char *end;
    
    for (long double n = strtold(p, &end); p != end; n = strtold(p, &end)) {
        p = end;
        if (errno == ERANGE) {
            printf("range error");
            errno = 0;
        }
        printf("n = %g\n", (double)n);
    }
}
 
/*

run:

n = 3.14
n = 8721.81
n = 52345.8

*/

 

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