Question

How to display the binary values of 8bit number in C

Answer 1

#include <stdio.h>

char *toBinFormat(int n);

int main(int argc, char **argv) 
{ 
    printf("The binary value of %d is %s\n", 7, toBinFormat(7));
    printf("The binary value of %d is %s\n", 30, toBinFormat(30));
    printf("The binary value of %d is %s\n", 32, toBinFormat(32));
    printf("The binary value of %d is %s\n", 64, toBinFormat(64));
    
    return(0);
}

char *toBinFormat(int n)
{
    static char binary_value[9]; // without static  binary_value is a local array 
                                 // that didn't exist after return
    int i;
    
    for(i = 0; i < 8; i++)
    {
        binary_value[i] = n & 0x80 ? '1' : '0';
        n <<= 1;
    }
    binary_value[i] = '\0';

    return binary_value;
}

/*
run:

The binary value of 7 is 00000111
The binary value of 30 is 00011110
The binary value of 32 is 00100000
The binary value of 64 is 01000000

*/

 

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