How to show only numbers that are present in two int arrays (intersect the ranges) in C++

1 Answer

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#include <iostream>
#include <algorithm>
#include <iterator>

using std::cout;
using std::endl;

int main()
{
	int arr1[] = { 1, 2, 3, 3, 5, 6, 7, 7, 8, 999 };
	int len1 = sizeof(arr1) / sizeof(int);

	int arr2[] = { 2, 3, 3, 3, 7, 7, 8, 9 };
	int len2 = sizeof(arr2) / sizeof(int);

	set_intersection(arr1, arr1 + len1, arr2, arr2 + len2, std::ostream_iterator<int>(cout, " "));

	cout << endl;

	return 0;
}

/*
run:

2 3 3 7 7 8

*/

 



answered Mar 2, 2018 by avibootz
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