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How to remove element from a list using remove_if() in C++

1 Answer

0 votes
#include <iostream>
#include <list>
#include <algorithm>

using std::list;
using std::cout;
using std::endl;

class N {   
private:
	int number;      
	int equal;
public:
	N(int n) : number(n), equal(0) {}
	
	bool operator() (int) {
		return ++equal == number;
	}
};

template <typename T>
inline void print(const T &data)
{
	for (const auto &element : data) {
		cout << element << ' ';
	}
	cout << endl;
}

int main()
{
	list<int> lst = { 1, 2, 3, 4, 5, 6, 7 };
	
	print(lst);

	list<int>::iterator pos;
	pos = remove_if(lst.begin(), lst.end(), N(6));
	lst.erase(pos, lst.end());

	print(lst);
}

/*
run:

1 2 3 4 5 6 7
1 2 3 4 5 7

*/

 



answered Jan 25, 2018 by avibootz

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