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How to use range() to create a list() of sequential numbers in Python



203 views
asked Dec 12, 2017 by avibootz
edited Dec 12, 2017 by avibootz
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2 Answers

0 votes 
lst = list(range(10))

print(lst)


'''
run:

[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]

'''

 



answered Dec 12, 2017 by avibootz
0 votes 
lst = list(range(5, 13))

print(lst)


'''
run:

[5, 6, 7, 8, 9, 10, 11, 12]

'''

 



answered Dec 12, 2017 by avibootz

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