How to calculate the hyperbolic sine of a number (an angle) in Python

1 Answer

0 votes
import math

print("math.sinh(math.pi / 6) = ", math.sinh(math.pi / 6))
print("math.sinh(math.pi / 2) = ", math.sinh(math.pi / 2))
print("math.sinh(math.pi / 180) = ", math.sinh(math.pi / 180))
print("math.sinh(-2 * math.pi / 4) = ", math.sinh(-2 * math.pi / 4))
print("math.sinh(+0) = ", math.sinh(0.0))
print("math.sinh(-0) = ", math.sinh(-0.0))
print("math.sinh(+1) = ", math.sinh(1.0))
print("math.sinh(-1) = ", math.sinh(-1.0))
print("math.sinh(math.log(2.0)) = ", math.sinh(math.log(2.0)))


'''
run:

math.sinh(math.pi / 6) =  0.5478534738880397
math.sinh(math.pi / 2) =  2.3012989023072947
math.sinh(math.pi / 180) =  0.01745417862959511
math.sinh(-2 * math.pi / 4) =  -2.3012989023072947
math.sinh(+0) =  0.0
math.sinh(-0) =  -0.0
math.sinh(+1) =  1.1752011936438014
math.sinh(-1) =  -1.1752011936438014
math.sinh(math.log(2.0)) =  0.75

'''

 



answered Oct 19, 2017 by avibootz
edited Oct 19, 2017 by avibootz
...