Question

How to decode a JSON string into an object in PHP

Answer 1

$json_string = '{"name": "Tim", "age": 42, "profession": "Programmer"}';
$object = json_decode($json_string);

printf('%s %d %s', $object->name, $object->age, $object->profession);


/*
run: 
 
Tim 42 Programmer
 
*/

 

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Answer 2

$json_string = '{"name": "Tim", "profession": "Programmer", "languages": ["PHP", "JAVA"]}';
$object = json_decode($json_string);
 
printf('%s %s %s %s', $object->name, $object->profession, 
                      $object->languages[0], $object->languages[1]);


/*
run: 
 
Tim Programmer PHP JAVA
 
*/

 

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Answer 3

$json_string = '{"name": "Tim", "profession": "Programmer", "languages": ["PHP", "JAVA"]}';
$object = json_decode($json_string);
                      
echo "<pre>";
var_dump($object);
echo "</pre>";

/*
run: 
 
object(stdClass)#1 (3) {
  ["name"]=>
  string(3) "Tim"
  ["profession"]=>
  string(10) "Programmer"
  ["languages"]=>
  array(2) {
    [0]=>
    string(3) "PHP"
    [1]=>
    string(4) "JAVA"
  }
}
 
*/

 

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