Question

How to dynamically allocate a 2D array of ints using an array of pointers in C

Answer 1

#include <stdio.h>
#include <stdlib.h>
  
int main(void)
{
    int row = 3, col = 4;
     
    int *arr[row];
    for (int i = 0; i < row; i++)
         arr[i] = (int *)malloc(col * sizeof(int));
  
    for (int i = 0; i < row; i++)
      for (int j = 0; j < col; j++)
            arr[i][j] = i + j;
  
    for (int i = 0; i < row; i++)
    {
       for (int j = 0; j < col; j++)
          printf("%d ", arr[i][j]);
       printf("\n"); 
    }
    
    for (int i = 0; i < row; i++)
         free(arr[i]);
 
    return 0;
}
  
    
/*
run:
   
0 1 2 3
1 2 3 4
2 3 4 5
 
*/

 

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