Question

How to dynamically allocate a 2D array of ints in C

Answer 1

#include <stdio.h>
#include <stdlib.h>
  
int main(void)
{
    int row = 3, col = 4;
    int *arr = (int *)malloc(row * col * sizeof(int));
 
    for (int i = 0; i < row; i++)
      for (int j = 0; j < col; j++)
            *(arr + i * col + j) = i + j;
 
    for (int i = 0; i < row; i++)
    {
       for (int j = 0; j < col; j++)
          printf("%d ", *(arr + i * col + j));
       printf("\n"); 
    }
    
    free(arr);
  
    return 0;
}
  
    
/*
run:
      
0 1 2 3
1 2 3 4
2 3 4 5
  
*/

 

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