Question

How to use method overloading in Java

Answer 1

public class MyClass {
    public static double GetArea(int x,int y) {
        return x * y;
    }
    
    public static double GetArea(int x) {
        return x * x;
    }
    
    public static double GetArea(int x,double y) {
        return x * y;
    }
    
    public static double GetArea(double x) {
        return x * x;
    }
    
    public static void main(String[] args) {
        System.out.println(GetArea(3, 6));
        
        System.out.println(GetArea(5, 4.7));
        
        System.out.println(GetArea(8));
        
        System.out.println(GetArea(3.14));
    }
}




/*
run:
  
18.0
23.5
64.0
9.8596
   
*/

 

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Answer 2

public class MyClass {
    public static int max(int num1, int num2) {
        System.out.print("max(int num1, int num2): ");
        
        if (num1 > num2)
            return num1;
        else
            return num2;
    }
    
    public static double max(double num1, double num2) {
        System.out.print("max(double num1, double num2): ");
        
        if (num1 > num2)
            return num1;
        else
            return num2;
    }
    
    public static double max(double num1, float num2) {
        System.out.print("max(double num1, float num2): ");
        
        if (num1 > num2)
            return num1;
        else
            return num2;
    }
    
    public static double max(double num1, double num2, double num3) {
        System.out.print("max(double num1, double num2, double num3): ");
        
        return max(max(num1, num2), num3);   
    }
    
    public static void main(String args[]) {
       System.out.println(max(5, 9));
       
       System.out.println(max(3.14, 2.99));
       
       System.out.println(max(3.14, 74.98F));
       
       System.out.println(max(3.14, 2.99, 4.87));
    }
}
 
 
 
 
 
/*
run:
 
max(int num1, int num2): 9
max(double num1, double num2): 3.14
max(double num1, float num2): 74.9800033569336
max(double num1, double num2, double num3): max(double num1, double num2): max(double num1, double num2): 4.87
 
*/

 

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