Question

How to check if a number is strong number or not in JavaScript

Answer 1

// Strong numbers are the numbers that the sum of factorial of its digits 
// is equal to the original number
 
// 145 is a strong number: 1 + 24 + 120 = 145
  
var n = 145, reminder, sum = 0;
 
var tmp = n;
 
while (n != 0)
{
    reminder = n % 10;
    sum = sum + factorial(reminder);
    n = Math.floor(n / 10);
}
if (sum == tmp)
    document.write(tmp + " is a strong number<br />");
else
    document.write(tmp + " is not a strong number<br />");
    
                
function factorial(n)
{
    var fact = 1;
 
    for (var i = 2; i <= n; i++)
        fact = fact * i;
 
    return fact;
}

/*
run:
 
145 is a strong number
  
*/

 

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