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How to print the ABC with pointers from the right (reverse) in C

1 Answer

0 votes
#include <stdio.h> 
 
void print(char *p);
 
int main(int argc, char **argv) 
{
    char *abc = "abcdefghijklmnopqrstuvwxyz";
  
    print(abc);
  
    return 0;
}

void print(char *p)
{
    char *start = p;
    while (*p) p++;
    
    p--; // from \0 to 'z'
    while (p >= start)
        printf("%c", *p--);
    
    printf("\n");
}

/*
run:

zyxwvutsrqponmlkjihgfedcba

*/


answered Mar 29, 2015 by avibootz
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