Question

How to generate an array of the alphabet letters in C

Answer 1

#include <stdio.h> 

int main(void)
{   
    char arr[26];
    
    for (int i = 'a'; i <= 'z'; i++)
        arr[i - 97] = i;
   
   for (int i = 0; i < 26; i++)
        printf("%c ", arr[i]);
     
    return 0;
}
  
        
/*
run:
     
a b c d e f g h i j k l m n o p q r s t u v w x y z

*/

 

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