Question

How to pass the command line arguments to a function in C

Answer 1

#include <stdio.h>
 
void print_args(int argc, char *argv[]);
 
int main(int argc, char **argv) 
{
    print_args(argc, argv);
  
    return 0;
}

void print_args(int argc, char *argv[])
{
    int i;
    
    for (i = 0; i < argc; i++)
        printf("argv[%d] = %s\n", i, argv[i]);
}

/*
run:

argv[0] = ./c_examples
argv[1] = arg1
argv[2] = arg2
argv[3] = arg3

*/

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