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How to extract the first letter from each word in a string with Java

3 Answers

0 votes
package javaapplication1;
 
public class JavaApplication1 {
 
    public static void main(String[] args) {
 
        String s = "java programming language"; 
         
        String firstLetters = GetFirstLetters(s);
         
        System.out.println(firstLetters);
    }
    public static String GetFirstLetters(String s) {
     
        StringBuilder sb = new StringBuilder();
         
        for(String word : s.split(" ")) {
            sb.append(word.charAt(0)).append(" ");         
        }
        return sb.toString();
    }
}
 
 
/*
 
run:
                    
j p l
  
*/

 



answered Jan 26, 2017 by avibootz
edited Jan 27, 2017 by avibootz
0 votes
package javaapplication1;
 
public class JavaApplication1 {
 
    public static void main(String[] args) {
 
        String s = "java programming language"; 
         
        String firstLetters = GetFirstLetters(s);
         
        System.out.println(firstLetters);
    }
    public static String GetFirstLetters(String s) {
     
        String firstLetters = "";
         
        for(String word : s.split(" "))
        {
          firstLetters += word.charAt(0) + " ";
        }
         
        return firstLetters;
    }
}
 
 
/*
 
run:
                    
j p l 
  
*/

 



answered Jan 26, 2017 by avibootz
edited Jan 27, 2017 by avibootz
0 votes
package javaapplication1;
 
import static java.lang.Character.toUpperCase;

public class JavaApplication1 {
 
    public static void main(String[] args) {
 
        String s = "java programming language"; 
         
        String firstLetters = GetFirstLetters(s);
         
        System.out.println(firstLetters);
    }
    public static String GetFirstLetters(String s) {
     
        StringBuilder sb = new StringBuilder();
         
        for(String word : s.split(" ")) {
            sb.append(toUpperCase(word.charAt(0))).append(" ");         
        }
        return sb.toString();
    }
}
 
 
/*
 
run:
                    
J P L 
  
*/

 



answered Jan 27, 2017 by avibootz

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