Question

How to use Math.incrementExact() that throw an ArithmeticException when the result overflows in Java

Answer 1

package javaapplication1;

public class JavaApplication1 {

    public static void main(String[] args) {

        try {

            int n = Math.incrementExact(100);
            System.out.println(n);

            n = Math.incrementExact(2147483647);
            System.out.println(n);

        } catch (Exception e) {
            System.out.println(e.toString());
        }
    }
}

/*
                  
run:
     
101
java.lang.ArithmeticException: integer overflow
         
 */

 

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