How to implement my own strlen() function to find the length of a string in C

3 Answers

0 votes
#include <stdio.h>
 
#define ROW 5
#define COL 10
 
int myStrlen(const char *s);

int main(void)
{
    char arr2d[ROW][COL] = {"c", "c++", "csharp", "java", "php"};
    
    printf("arr2d[0] = %s len = %d\n", arr2d[0], myStrlen(arr2d[0]));
    printf("arr2d[1] = %s len = %d\n", arr2d[1], myStrlen(arr2d[1]));
    printf("arr2d[2] = %s len = %d\n", arr2d[2], myStrlen(arr2d[2]));
    printf("arr2d[3] = %s len = %d\n", arr2d[3], myStrlen(arr2d[3]));
    printf("arr2d[4] = %s len = %d\n", arr2d[4], myStrlen(arr2d[4]));
        
    return 0;
}

int myStrlen(const char *s)
{
    int i = 0;
    
    while (*s++) i++;
    
    return i;
}


/*
run:
   
arr2d[0] = c len = 1
arr2d[1] = c++ len = 3
arr2d[2] = csharp len = 6
arr2d[3] = java len = 4
arr2d[4] = php len = 3

*/


answered Mar 3, 2015 by avibootz
0 votes
#include <stdio.h>
  
#define ROW 5
#define COL 10
  
int myStrlen(const char *s);
 
int main(void)
{
    char arr2d[ROW][COL] = {"c", "c++", "csharp", "java", "php"};
     
    printf("arr2d[0] = %s len = %d\n", arr2d[0], myStrlen(arr2d[0]));
    printf("arr2d[1] = %s len = %d\n", arr2d[1], myStrlen(arr2d[1]));
    printf("arr2d[2] = %s len = %d\n", arr2d[2], myStrlen(arr2d[2]));
    printf("arr2d[3] = %s len = %d\n", arr2d[3], myStrlen(arr2d[3]));
    printf("arr2d[4] = %s len = %d\n", arr2d[4], myStrlen(arr2d[4]));
         
    return 0;
}
 
int myStrlen(const char *s)
{
    int i = 0;
     
    while (s[i++] != '\0');
     
    return --i;
}
 
 
/*
run:
    
arr2d[0] = c len = 1
arr2d[1] = c++ len = 3
arr2d[2] = csharp len = 6
arr2d[3] = java len = 4
arr2d[4] = php len = 3
 
*/

 



answered Nov 6, 2015 by avibootz
0 votes
#include <stdio.h>
   
#define ROW 5
#define COL 10
   
int myStrlen(const char *s);
  
int main(void)
{
    char arr2d[ROW][COL] = {"c", "c++", "csharp", "java", "php"};
      
    printf("arr2d[0] = %s len = %d\n", arr2d[0], myStrlen(arr2d[0]));
    printf("arr2d[1] = %s len = %d\n", arr2d[1], myStrlen(arr2d[1]));
    printf("arr2d[2] = %s len = %d\n", arr2d[2], myStrlen(arr2d[2]));
    printf("arr2d[3] = %s len = %d\n", arr2d[3], myStrlen(arr2d[3]));
    printf("arr2d[4] = %s len = %d\n", arr2d[4], myStrlen(arr2d[4]));
          
    return 0;
}
  
int myStrlen(const char *s)
{
    int i = 0;
      
    for (i = 0; *s != '\0'; s++, i++);

    return i; 
}
  
  
/*
run:
     
arr2d[0] = c len = 1
arr2d[1] = c++ len = 3
arr2d[2] = csharp len = 6
arr2d[3] = java len = 4
arr2d[4] = php len = 3
  
*/

 



answered Nov 19, 2015 by avibootz

Related questions

2 answers 815 views
1 answer 108 views
108 views asked Dec 18, 2022 by avibootz
3 answers 304 views
2 answers 290 views
1 answer 125 views
125 views asked Sep 20, 2021 by avibootz
...