How to compare two float arrays using a tolerance in TypeScript

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/*
    Compare two float arrays element-by-element using a tolerance.
    Floating‑point values often differ slightly due to rounding,
    so two numbers are considered "equal" when their absolute
    difference is below the chosen threshold.
*/

// Compares two float arrays and returns true if all elements match within tolerance
function compareFloatArrays(a: number[], b: number[], tolerance: number): boolean {
    // If lengths differ, arrays cannot be equal
    if (a.length !== b.length) {
        return false;
    }

    // Compare each element using absolute difference
    for (let i: number = 0; i < a.length; i++) {
        const diff: number = Math.abs(a[i] - b[i]);

        // If any element differs more than tolerance, arrays are not equal
        if (diff > tolerance) {
            return false;
        }
    }

    // All elements matched within tolerance
    return true;
}

// Prints the comparison result
function printComparison(result: boolean): void {
    if (result) {
        console.log("Arrays are equal within tolerance.");
    } else {
        console.log("Arrays differ.");
    }
}

// Example arrays
const floatArr1: number[] = [
    12314.9872,
    3.14,
    12387.91371,
    8876.579013
];

const floatArr2: number[] = [
    12314.9872,
    3.14,
    12387.91372,
    8876.579013
];

// Tolerance chosen for comparison
const tolerance: number = 0.001;

// Perform comparison
const result: boolean = compareFloatArrays(floatArr1, floatArr2, tolerance);

// Output result
printComparison(result);



/*
run:

Arrays are equal within tolerance.

*/

 



answered Sep 8 by avibootz
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