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How to compare two float arrays using a tolerance in C

1 Answer

0 votes
#include <stdio.h>
#include <math.h>

/*
    Compare two float arrays element-by-element using a tolerance.
    Floating-point values often differ slightly due to rounding,
    so two numbers are considered "equal" when their absolute
    difference is below the chosen threshold.
*/

// Compares two float arrays and returns 1 if all elements match within tolerance
int compareFloatArrays(
    const float* a,
    const float* b,
    size_t length,
    float tolerance
) {
    // Loop through each element and compare using absolute difference
    for (size_t i = 0; i < length; ++i) {
        float diff = fabsf(a[i] - b[i]);

        // If any element differs more than tolerance, arrays are not equal
        if (diff > tolerance) {
            return 0; // false
        }
    }

    // All elements matched within tolerance
    return 1; // true
}

// Prints the comparison result
void printComparison(int result) {
    if (result) {
        printf("Arrays are equal within tolerance.\n");
    } else {
        printf("Arrays differ.\n");
    }
}

int main(void) {
    // Example arrays
    float floatArr1[] = {
        12314.9872f,
        3.14f,
        12387.91372f,
        8876.579013f
    };

    float floatArr2[] = {
        12314.9872f,
        3.14f,
        12387.91371f,
        8876.579013f
    };

    // Number of elements
    size_t length = sizeof(floatArr1) / sizeof(floatArr1[0]);

    // Tolerance chosen for comparison
    float tolerance = 0.001f;

    // Perform comparison
    int result = compareFloatArrays(floatArr1, floatArr2, length, tolerance);

    // Output result
    printComparison(result);

    return 0;
}


/*
run:

Arrays are equal within tolerance.

*/

 



answered Sep 8 by avibootz
edited Sep 8 by avibootz
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