How to replace all matches of a pattern with a string using replaceAll() in Java

1 Answer

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package javaapplication1;

public class JavaApplication1 {

    public static void main(String[] args) {

        try {

            String s = "x0101y x1111y a1111y x0000y x1111w";

            s = s.replaceAll("x\\d\\d\\d\\dy", "x@@@y");
            System.out.println(s);

        } catch (Exception e) {
            System.out.print(e.toString());
        }
    }
}

/*
             
run:

x@@@y x@@@y a1111y x@@@y x1111w
    
 */

 



answered Nov 25, 2016 by avibootz
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