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How to build sparse array in Scala

1 Answer

0 votes
//
// A sparse array stores only non‑zero values.
// Scala's Map[Int, Int] is a natural fit:
//   - Keys represent indices that actually exist
//   - Values represent stored data
//   - Lookup and insertion are fast
//

object SparseToDense {

  // Sparse array type
  type SparseArray = Map[Int, Int]

  // Dense array type
  type DenseArray  = Vector[Int]

  /*
      buildDense:
      Converts sparse → dense.

      Steps:
      1. Find the maximum index in the sparse structure
      2. Allocate a dense vector of size maxIndex + 1
      3. Fill with zeros
      4. Copy sparse values into their positions
  */
  def buildDense(sa: SparseArray): DenseArray = {
    // Find largest index
    val maxIndex: Int = if (sa.isEmpty) 0 else sa.keys.max

    // Allocate dense vector filled with zeros
    val dense: DenseArray = Vector.fill(maxIndex + 1)(0)

    // Copy sparse values
    dense.zipWithIndex.map { case (_, idx) =>
      sa.getOrElse(idx, 0)
    }
  }

  def main(args: Array[String]): Unit = {
    // Sparse entries (zero values omitted)
    val sa: SparseArray = Map(
      2  -> 10,
      10 -> 7,
      8  -> 42,
      3  -> 5
    )

    val dense: DenseArray = buildDense(sa)

    println("Dense array:")
    print("[ ")
    dense.foreach(v => print(s"$v "))
    println("]")
  }
}


/*
run:

Dense array:
[ 0 0 10 5 0 0 0 0 42 0 7 ]

*/

 



answered Aug 15 by avibootz
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