# Compute the median of three numbers.
# The median is the value that is neither the smallest nor the largest.
# This approach keeps the logic compact and easy to follow.
def median_of_three_numbers(a, b, c)
# Ruby's built-in min/max handle multiple arguments cleanly.
smallest = [a, b, c].min
largest = [a, b, c].max
# The median is the one that is not equal to smallest or largest.
# This avoids extra branching and keeps the intent clear.
return a if a != smallest && a != largest
return b if b != smallest && b != largest
c # If neither a nor b is the median, c must be.
end
# Test cases
tests = [
[1, 1, 1],
[10, 3, 7],
[10, -10, -10],
[3, 3, 5]
]
tests.each do |(x, y, z)|
result = median_of_three_numbers(x, y, z)
puts "The median of [#{x}, #{y}, #{z}] is #{result}"
end
=begin
run:
The median of [1, 1, 1] is 1
The median of [10, 3, 7] is 7
The median of [10, -10, -10] is -10
The median of [3, 3, 5] is 5
=end
