How to specify precision with String.format() in Java

1 Answer

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package javaapplication1;

import java.io.IOException;

public class JavaApplication1 {

    public static void main(String[] args) throws IOException {

        try {

            double pi = 3.14159265359;

            String s = String.format("%.5f", pi);
            System.out.println(s);

        } catch (Exception e) {
            System.out.print(e.toString());
        }
    }
}

/*
           
run:
     
3.14159
  
 */

 



answered Nov 20, 2016 by avibootz

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