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How to find the Nth set bit in a 64‑bit integer with PHP

1 Answer

0 votes
/*
    countTrailingZeros:
    -------------------
    Returns the number of trailing zeros in a 64‑bit integer.
    Equivalent to C++ std::countr_zero or GCC __builtin_ctzll.

    Algorithm:
        - Isolate lowest set bit: x & -x
        - Its index is log2(lowest_bit)
*/
function countTrailingZeros(int $x): int {
    $lowest = $x & (-$x);      // isolate lowest set bit
    
    return (int) log($lowest, 2);  // index (0–63)
}

/*
    findNthSetBit64:
    ----------------
    Given:
        - x : a 64-bit integer
        - n : which set bit to find (1-based index)

    Returns:
        A 64-bit mask with ONLY the Nth set bit of x turned on.
        If n is larger than the number of set bits, returns 0.

    Algorithm:
        - Use countTrailingZeros(x) to locate the lowest set bit.
        - Remove that bit using x &= (x - 1).
        - When we reach the Nth one, return 1 << index.
*/
function findNthSetBit64(int $x, int $n): int {
    while ($x !== 0) {

        $index = countTrailingZeros($x);

        $n--;
        if ($n === 0) {
            return 1 << $index;
        }

        // Remove the lowest set bit
        $x &= ($x - 1);
    }

    return 0;
}

/*
    toBinary64:
    -----------
    Convert integer to a padded 64-bit binary string.
*/
function toBinary64(int $x): string {
    $s = decbin($x);
    
    return str_pad($s, 64, '0', STR_PAD_LEFT);
}


// --------------------
// Main 
// --------------------

$value =
    0b0000000000000000000010000000000000001101001101101100100010100000;

$n = 4;

$result = findNthSetBit64($value, $n);

echo "Input value:  " . toBinary64($value) . PHP_EOL;
echo "N = $n" . PHP_EOL;
echo "Result mask:  " . toBinary64($result) . PHP_EOL;



/*
run:

Input value:  0000000000000000000010000000000000001101001101101100100010100000
N = 4
Result mask:  0000000000000000000000000000000000000000000000000100000000000000

*/

 



answered Jul 25 by avibootz
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