How to sort an array that consists of only 0s and 1s in Swift

1 Answer

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import Foundation

// Function to sort an array containing only 0s and 1s
func sortBinaryArray(_ arr: inout [Int]) {
    var left = 0                      // Index to track the left side
    var right = arr.count - 1        // Index to track the right side

    while left < right {
        // If the left index is at 0, move it forward
        if arr[left] == 0 {
            print("left: \(left)")
            left += 1
        }
        // If the right index is at 1, move it backward
        else if arr[right] == 1 {
            print("right: \(right)")
            right -= 1
        }
        // If left is 1 and right is 0, swap them
        else {
            arr.swapAt(left, right)
            print("swap() left: \(left) right: \(right)")
            left += 1
            right -= 1
        }
    }
}

func main() {
    // Input: Binary array
    var arr: [Int] = [1, 0, 1, 0, 1, 0, 0, 1, 0]

    // Sort the binary array
    sortBinaryArray(&arr)

    // Output the sorted array
    print("Sorted array: ", terminator: "")
    for num in arr {
        print("\(num) ", terminator: "")
    }
}

main()



/*
run:

swap() left: 0 right: 8
left: 1
right: 7
swap() left: 2 right: 6
left: 3
swap() left: 4 right: 5
Sorted array: 0 0 0 0 0 1 1 1 1 

*/

 



answered Sep 3 by avibootz
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