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How to find pythagorean triplet for which a + b + c = 1000 in Kotlin

1 Answer

0 votes
fun main() {
    // Define the total sum of the Pythagorean triplet (a + b + c = 1000)
    val sum = 1000

    // Loop through possible values for 'a'
    // We only check up to sum/3 because 'a' must be the smallest in the triplet
    for (a in 1..(sum / 3)) {

        // Loop through possible values for 'b', starting just above 'a'
        // It goes only up to sum/2 to avoid redundancy and ensure 'b < c'
        for (b in (a + 1)..(sum / 2)) {

            // Calculate 'c' as the remaining value so that a + b + c = sum
            val c = sum - a - b

            // Check if the triplet (a, b, c) satisfies the Pythagorean condition
            // That is, a² + b² must equal c²
            if (a * a + b * b == c * c) {
                println("($a^2 = ${a * a}) + ($b^2 = ${b * b}) = $c^2 = ${c * c}")
                println("a = $a, b = $b, c = $c")
                println("$a + $b + $c = ${a + b + c}")
            }
        }
    }
}


 
  
/*
run:
 
(200^2 = 40000) + (375^2 = 140625) = 425^2 = 180625
a = 200, b = 375, c = 425
200 + 375 + 425 = 1000

*/

 



answered Jul 25, 2025 by avibootz
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