How to implement a function that convert an int to char array using C

1 Answer

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#include <stdio.h>
#include <stdlib.h>
#include <math.h>

char *toCharArray(int n) {
    int len = log10(n) + 1;
    char *arr = calloc(len, sizeof(char));

    for (int i = len - 1; i >= 0; i--, n /= 10) {
        arr[i] = (n % 10) + '0';
    }
    return arr;
}

int main() {
    int n = 90651;

    char *p = toCharArray(n);

    puts(p);

    free(p);

    return 0;
}




/*
run:

90651

*/

 



answered Jun 19, 2021 by avibootz

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