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How to declare, initialize and print one-dimensional array of integers in PHP

3 Answers

0 votes
$arr = array(2, 234, 48, 17, 98, 918, 800, 12237, 100, 28);
 
echo "<pre>";  
print_r($arr);
echo "</pre>";


             
/*
run:

Array
(
    [0] => 2
    [1] => 234
    [2] => 48
    [3] => 17
    [4] => 98
    [5] => 918
    [6] => 800
    [7] => 12237
    [8] => 100
    [9] => 28
)
 
*/

 



answered Feb 3, 2016 by avibootz
0 votes
$arr = array(2, 234, 48, 17, 98, 918, 800, 12237, 100, 28);
 
for ($i = 0; $i < count($arr); $i++) 
    echo "arr[$i] = $arr[$i] <br />";
             
/*
run:

arr[0] = 2
arr[1] = 234
arr[2] = 48
arr[3] = 17
arr[4] = 98
arr[5] = 918
arr[6] = 800
arr[7] = 12237
arr[8] = 100
arr[9] = 28 
 
*/

 



answered Feb 3, 2016 by avibootz
0 votes
$arr = array(); 

for ($i = 0; $i < 10; $i++) 
    $arr[$i] = $i + 1;

for ($i = 0; $i < 10; $i++) 
    echo "arr[$i] = $arr[$i] <br />";

/*
run:
 
arr[0] = 1
arr[1] = 2
arr[2] = 3
arr[3] = 4
arr[4] = 5
arr[5] = 6
arr[6] = 7
arr[7] = 8
arr[8] = 9
arr[9] = 10 
  
*/

 



answered Feb 6, 2016 by avibootz
...