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How to print the first string from a deque of strings in C++

3 Answers

0 votes
#include <iostream>  
#include <string>  
#include <deque> 

using std::deque;
using std::string;
using std::cout;

int main()
{
	deque<string> dq;

	dq.push_back(string("c"));
	dq.push_back(string("c++"));
	dq.push_back(string("c#"));
	dq.push_back(string("java"));

	std::deque<std::string>::iterator it = dq.begin();

	printf_s(std::string(*it).c_str());

	cout << std::endl;

	return 0;
}

/*
run:

c

*/

 




answered Jan 4 by avibootz
0 votes
#include <iostream>  
#include <string>  
#include <deque> 

using std::deque;
using std::string;
using std::cout;

int main()
{
	deque<string> dq{ "c++", "c", "assembly" };

	cout << dq.front() << std::endl;

	return 0;
}

/*
run:

c++

*/

 




answered Jan 4 by avibootz
0 votes
#include <iostream>  
#include <string>  
#include <deque> 

using std::deque;
using std::string;
using std::cout;

int main()
{
	deque<string> dq{ "c++", "c", "assembly" };

	std::deque<std::string>::iterator it = dq.begin();

	printf_s(it->c_str());

	cout << std::endl;

	return 0;
}

/*
run:

c++

*/

 




answered Jan 4 by avibootz
...