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How to initialized pointer with the first element of an unnamed array of ints in C

1 Answer

0 votes
#include <stdio.h>

int main(void) 
{
    int *p = (int [3]){ 13, 150, 995 };
    
    printf("%d\n", *(p));
    printf("%d\n", *(p + 1));
    printf("%d\n\n", *(p + 2));

    printf("%d\n", p[0]);
    printf("%d\n", p[1]);
    printf("%d\n", p[2]);
    
    return 0;
}
    
/*
run:
 
13
150
995

13
150
995

*/

 




answered Aug 25, 2017 by avibootz
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