Question

How to swap two numbers without using a third variable (temp) in C#

Answer 1

using System;

public class Program {
    public static void Main(string[] args) {
        Console.WriteLine("Enter two numbers:");
        int n1 = Convert.ToInt32(Console.ReadLine());
        int n2 = Convert.ToInt32(Console.ReadLine());

        n1 = n1 + n2;
        n2 = n1 - n2;
        n1 = n1 - n2;

        Console.WriteLine("n1 = {0}", n1);
        Console.WriteLine("n2 = {0}", n2);
    }
}



/*
run:
   
Enter two numbers:
3
7
n1 = 7
n2 = 3
      
*/

 

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Answer 2

using System;

public class Program {
    public static void Main(string[] args) {
        int a = 5, b = 13;
 
        a = a + b;
        b = a - b;
        a = a - b;

        Console.WriteLine("a = {0}", a);
        Console.WriteLine("b = {0}", b);
    }
}



/*
run:
   
a = 13
b = 5
      
*/

 

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Answer 3

using System;

public class Program {
    public static void Main(string[] args) {
        int a = 5, b = 13;
 
        a = a + b - (b = a);

        Console.WriteLine("a = {0}", a);
        Console.WriteLine("b = {0}", b);
    }
}


/*
run:
   
a = 13
b = 5
      
*/

 

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Answer 4

using System;

public class Program {
    public static void Main(string[] args) {
        int a = 5, b = 13;
 
        a = a ^ b;
        b = a ^ b;
        a = b ^ a;

        Console.WriteLine("a = {0}", a);
        Console.WriteLine("b = {0}", b);
    }
}


/*
run:
   
a = 13
b = 5
      
*/

 

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Answer 5

using System;

public class Program {
    public static void Main(string[] args) {
        int a = 5, b = 13;
 
        a = b - ~a - 1;
        b = a + ~b + 1;
        a = a + ~b + 1;

        Console.WriteLine("a = {0}", a);
        Console.WriteLine("b = {0}", b);
    }
}


/*
run:
   
a = 13
b = 5
      
*/

 

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