Question

How to split a string into a string array using a set of characters in Java

Answer 1

class Main {
    public static void main(String[] args) {
    try {
 
          String str = "java,c,@c++:,php!,c#,c-3po";
 
          String arr[] = str.split("[,:@!]");

          for (String s : arr) {
                System.out.println(s);
          }
 
    } catch (Exception e) {
          System.out.println(e.toString());
    }
  }
}


/*
run:

java
c

c++

php

c#
c-3po

*/

 

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Answer 2

class Main {
    public static void main(String[] args) {
    try {
 
          String str = "java,c,@c++:,php!,c#,c-3po";
 
          String arr[] = str.split("[,:@!]");

          for (String s : arr) {
              if (!"".equals(s))
                  System.out.println(s);
          }
 
    } catch (Exception e) {
          System.out.println(e.toString());
    }
  }
}


/*
run:

java
c
c++
php
c#
c-3po

*/

 

70+ SQL courses for beginners and professionals

Answer 3

import java.util.ArrayList;
import java.util.Arrays;
import java.util.Collections;
import java.util.List;

class Main {
    public static void main(String[] args) {
    try {
 
          String str = "java,c,@c++:,php!,c#,c-3po";
 
          String arr[] = str.split("[,:@!]");

          final List<String> list = new ArrayList<String>();
          
          Collections.addAll(list, arr);
          list.removeAll(Arrays.asList(""));
          arr = list.toArray(new String[list.size()]);

          for (String s : arr) {
                System.out.println(s);
            }
 
    } catch (Exception e) {
          System.out.println(e.toString());
    }
  }
}


/*
run:

java
c
c++
php
c#
c-3po

*/

 

70+ SQL courses for beginners and professionals