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How to find the frequency of each digit (0–9) in a number with C#

1 Answer

0 votes
using System;

class DigitFrequency
{
    /*
        Function: countDigitFrequency
        Purpose:  Counts how many times each digit (0–9) appears in a number.
        Parameters:
            - n: the number whose digits we want to count
            - freq: an array of size 10 that stores the frequency of each digit
                    freq[0] = count of digit '0'
                    freq[1] = count of digit '1'
                    ...
                    freq[9] = count of digit '9'
        Explanation:
            We repeatedly extract the last digit using n % 10,
            then remove that digit using n / 10.
    */
    static void CountDigitFrequency(int n, int[] freq)
    {
        // Process each digit of the number
        while (n > 0)
        {
            int digit = n % 10;   // extract last digit
            freq[digit]++;        // increase its frequency
            n /= 10;              // remove last digit
        }
    }

    static void Main()
    {
        int n = 79712622;   // the number we want to analyze

        int[] freq = new int[10];    // array to store digit frequencies

        // Call the function to count digit frequencies
        CountDigitFrequency(n, freq);

        // Display the result
        Console.WriteLine("Digit frequencies in " + n + ":\n");

        for (int i = 0; i < 10; i++)
        {
            if (freq[i] != 0)
                Console.WriteLine("Digit " + i + " occurs " + freq[i] + " times");
        }
    }
}


/*
run:

Digit frequencies in 79712622:

Digit 1 occurs 1 times
Digit 2 occurs 3 times
Digit 6 occurs 1 times
Digit 7 occurs 2 times
Digit 9 occurs 1 times

*/

 



answered Jul 2 by avibootz
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