Welcome to collectivesolver - Programming & Software Q&A with code examples. A website with trusted programming answers. All programs are tested and work.

Contact: aviboots(AT)netvision.net.il

Semrush - keyword research tool

Turn ChatGPT, Claude, Gemini, And CoPilot Into Your Personal Assistant, Business Coach, Content Creator, And More

AFFILIATE MARKETING Your all-in-one performance engine Manage affiliates, creators, and customer referrals in one unified platform—turning every partnership into measurable growth
Secure & Reliable Web Hosting, Free Domain, Free SSL, 1-Click WordPress Install, Expert 24/7 Support

Boost your online presence with premium web hosting and servers

Disclosure: My content contains affiliate links.

42,690 questions

55,449 answers

573 users

How to find the frequency of each digit (0–9) in a number with Java

1 Answer

0 votes
/**
    Function: countDigitFrequency
    Purpose:  Counts how many times each digit (0–9) appears in a number.
    Parameters:
        - n: the number whose digits we want to count
        - freq: an array of size 10 that stores the frequency of each digit
                freq[0] = count of digit '0'
                freq[1] = count of digit '1'
                ...
                freq[9] = count of digit '9'
    Explanation:
        We repeatedly extract the last digit using n % 10,
        then remove that digit using n / 10.
*/
public class DigitFrequency {

    public static void countDigitFrequency(int n, int[] freq) {
        // Process each digit of the number
        while (n > 0) {
            int digit = n % 10;   // extract last digit
            freq[digit]++;        // increase its frequency
            n /= 10;              // remove last digit
        }
    }

    public static void main(String[] args) {

        int n = 79712622;   // the number we want to analyze

        int[] freq = new int[10];    // array to store digit frequencies

        // Call the function to count digit frequencies
        countDigitFrequency(n, freq);

        // Display the result
        System.out.println("Digit frequencies in " + n + ":\n");

        for (int i = 0; i < 10; i++) {
            if (freq[i] != 0)
                System.out.println("Digit " + i + " occurs " + freq[i] + " times");
        }
    }
}


/*
run:

Digit frequencies in 79712622:

Digit 1 occurs 1 times
Digit 2 occurs 3 times
Digit 6 occurs 1 times
Digit 7 occurs 2 times
Digit 9 occurs 1 times

*/

 



answered Jul 2 by avibootz
...