How to find the smallest number that is evenly divisible by all of the numbers from 1 to 10 in Kotlin

1 Answer

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fun lcm(a: Int, b: Int): Int {
    var lmc = maxOf(a, b) // Start with the greater of the two numbers

    // Loop indefinitely until we find the LCM
    while (lmc % a != 0 || lmc % b != 0) {
        lmc++ // Increment and check the next number
    }

    return lmc // Return the LCM
}

fun main() {
    var result = 1

    // Iterate through numbers 1 to 10
    for (i in 1..10) {
        result = lcm(result, i) // Update result with LCM of current range
    }

    println("The Least Common Multiple (LCM) of numbers from 1 to 10 is: $result")
}

   
      
/*
run:

The Least Common Multiple (LCM) of numbers from 1 to 10 is: 2520
  
*/

 



answered May 11 by avibootz
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