How to pad an array to a specified length with a given value in C

1 Answer

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#include <stdio.h>
#include <stdlib.h>

int* arrayPad(const int* arr, int original_size, int size, int value) {
    int* paddedArray = (int*)malloc(size * sizeof(int));
    if (paddedArray == NULL || size < original_size) {
        puts("malloc error");
        return NULL;
    }

    for (int i = 0; i < original_size; ++i) {
        paddedArray[i] = arr[i];
    }
    for (int i = original_size; i < size; ++i) {
        paddedArray[i] = value;
    }
    
    return paddedArray;
}

int main() {
    int arr[] = {1, 2, 3};
    int original_size = sizeof(arr) / sizeof(arr[0]);
    int size = 5;
    int* paddedArray = arrayPad(arr, original_size, size, 0);

    if (paddedArray != NULL) {
        for (int i = 0; i < size; ++i) {
            printf("%d ", paddedArray[i]);
        }
        // Free the allocated memory
        free(paddedArray);
    }

    return 0;
}

       
/*
run:
    
1 2 3 0 0 
   
*/

 



answered Feb 4 by avibootz
edited Feb 4 by avibootz
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