Question

How to double a number using binary shift left operation in C

Answer 1

#include <stdio.h>

void print_bits(int n, int size) {
    for (int i = 1 << (size - 1); i > 0; i = i / 2) {
        (n & i) ? printf("1") : printf("0");
    }
}

int main(void)
{
    int n = 7;

    printf("n = %d\n", n);
    print_bits(n, 4);
    printf("\n");

    n = n << 1; // double the number
    printf("n = %d\n", n);
    print_bits(n, 4);

    return 0;
}




/*
run:

n = 7
0111
n = 14
1110

*/

 

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