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How to count all distinct pairs from array with specific difference between them in JavaScript

1 Answer

0 votes
class CArray {
    countPairsWithSpecificDifference(arr, difference) {
        let count = 0; 
        const size = arr.length;
         
        for (let i = 0; i < size; i++) {        
            for (let j = i + 1; j < size; j++) {
                if (arr[i] - arr[j] == difference || arr[j] - arr[i] == difference) {
                      count++; 
                }
            }
        } 
        return count; 
    }
}
 
 
const obj = new CArray();
const arr = [25, 16, 8, 12, 20, 17, 0, 4, 21, 26];
const difference = 4;
 
// 7 pairs with difference 4: {25, 21}, {16, 12}, {16, 20}, {8, 12}, {8, 4}, {17, 21} {0, 4} 
 
console.log(obj.countPairsWithSpecificDifference(arr, difference));
 
 
 
  
/*
run:
    
7
    
*/

 





answered Dec 1, 2021 by avibootz
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