Question

How to sort the digits of a number in descending order with JavaScript

Answer 1

let n = 38275;
let s = n.toString();

let arr = s.split('');
arr.sort();
arr.reverse();
s = arr.join('');

n = parseInt(s, 10);
 
console.log(n);

 
 
/*
run:
 
87532
 
*/

 

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Answer 2

function sortNumberDescending(num) {
	return Number(num.toString().split('').sort((a, b) => b - a).join(''));
}

let n = 38275;

n = sortNumberDescending(n)
  
console.log(n);
 
  
  
  
/*
run:
  
87532
  
*/

 

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Answer 3

function sortNumberDescending(num) {
	return parseInt(num.toString().split('').sort().reverse().join(''));
}

let n = 398275;

n = sortNumberDescending(n)
  
console.log(n);
 
  
  
  
/*
run:
  
987532
  
*/

 

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