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How to find all duplicate elements in int array using C++

1 Answer

0 votes
#include <iostream>

// Function to find and print duplicates
void findDuplicates(const int arr[], int len, int duplicate[]) {
    for (int i = 0; i < len; i++) {
        for (int j = i + 1; j < len; j++) {
            if (arr[i] == arr[j]) {
                duplicate[arr[i]] = 1; // Mark as duplicate
                break;
            }
        }
    }
}

int main() {
    int arr[] = { 1, 1, 2, 3, 4, 4, 4, 5, 6, 6, 7, 7, 7 };
    int len = sizeof(arr) / sizeof(arr[0]);
    
    int duplicate[10] = {0}; // Array to store duplicate flags

    findDuplicates(arr, len, duplicate); // Call the function
    
    std::cout << "Duplicate numbers found:\n";
    for (int i = 0; i < 10; i++) {
        if (duplicate[i])
            std::cout << i << std::endl;
    }
}

 
 
/*
run:
 
Duplicate numbers found:
1
4
6
7
 
*/

 



answered Feb 17, 2019 by avibootz
edited May 22, 2025 by avibootz
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