How to find an element that appears once in an array of elements that appears three times in TypeScript

1 Answer

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const findElementThatAppearsOnceInArray = (arr: number[]) => {
    const map: any = new Map();
 
    for (const x of arr) {
        map.set(x, (map.get(x) || 0) + 1);
    }
 
    for (const [key, value] of map) {
        if (value === 1) {
            return key;
        }
    }
 
    return -1;
};
 
const arr: number[] = [3, 5, 5, 2, 7, 3, 2, 8, 8, 3, 2, 5, 8];
 
console.log(findElementThatAppearsOnceInArray(arr));
 
 
 
/*
run:
 
7
 
*/

 



answered Jul 8, 2024 by avibootz
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